If l = lim_{theta rightarrow 0} left( frac{3 | vedclass

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(B) We know that $\sin(3	heta) = 3 \sin 	heta - 4 \sin^3 	heta$. Thus,$l = \lim_{	heta ightarrow 0} \frac{\sin(3	heta)}{	heta} = \lim_{	heta

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$x^2 - 5x + 6 = 0$

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(B) We know that $\sin(3	heta) = 3 \sin 	heta - 4 \sin^3 	heta$. Thus,$l = \lim_{	heta ightarrow 0} \frac{\sin(3	heta)}{	heta} = \lim_{	heta ightarrow 0} \frac{\sin(3	heta)}{3	heta} 	imes 3 = 1 	imes 3 = 3$. We also know that $	an(2	heta) = \frac{2 	an 	heta}{1 - 	an^2 	heta}$. Thus,$m = \lim_{	heta ightarrow 0} \frac{	an(2	heta)}{	heta} = \lim_{	heta ightarrow 0} \frac{	an(2	heta)}{2	heta} 	imes 2 = 1 	imes 2 = 2$. The quadratic equation with roots $l=3$ and $m=2$ is given by $(x - l)(x - m) = 0$. $(x - 3)(x - 2) = 0$ $x^2 - 2x - 3x + 6 = 0$ $x^2 - 5x + 6 = 0$.

If $l = \lim_{\theta \rightarrow 0} \left( \frac{3 \sin \theta - 4 \sin^3 \theta}{\theta} \right)$ and $m = \lim_{\theta \rightarrow 0} \left( \frac{2 \tan \theta}{\theta(1 - \tan^2 \theta)} \right)$,find the quadratic equation whose roots are $l$ and $m$.

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