If $A$ and $B$ are any two events of a sample space,then the set-theoretic description for the event: "Exactly one of the events $A, B$ occurs" is
(Here $E^c$ denotes the complement of the event $E$)
(Here $E^c$ denotes the complement of the event $E$)
- A$A \cap B^c$
- B$(A-B) \cup (A \cup B)$
- C$(A \cap B^c) \cup (A^c \cap B)$
- D$(A \cap B)^c \cup (A^c \cap B^c)$
Explore More
Similar Questions
If $A = \{3, 6, 9, 12, 15, 18, 21\}$,$B = \{4, 8, 12, 16, 20\}$,$C = \{2, 4, 6, 8, 10, 12, 14, 16\}$,and $D = \{5, 10, 15, 20\}$,find $B - C$.
Easy
View SolutionIf $A = \{x : x \text{ is a multiple of } 4\}$ and $B = \{x : x \text{ is a multiple of } 6\}$,then $A \cap B$ consists of all multiples of:
Medium
View SolutionFind the union of each of the following pairs of sets:
$A = \{ x : x \text{ is a natural number and a multiple of } 3 \}$
$B = \{ x : x \text{ is a natural number less than } 6 \}$
$A = \{ x : x \text{ is a natural number and a multiple of } 3 \}$
$B = \{ x : x \text{ is a natural number less than } 6 \}$
Easy
View SolutionConsider the sets $X$ and $Y$ where $X = \{ \text{Ram, Geeta, Akbar} \}$ and $Y = \{ \text{Geeta, David, Ashok} \}$. Find $X \cap Y$.
Easy
View SolutionIf $A$ and $B$ are not disjoint sets,then $n(A \cup B)$ is equal to
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo