If A = begin{bmatrix} 1 & -2 & 2 2 & -6 & 5 | vedclass

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(C) To find the adjoint of matrix $A$,we first find the cofactor of each element of $A$.Let $C_{ij}$ be the cofactor of the element $a_{ij}$.$C_{11} =

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$\begin{bmatrix} -24 & 8 & 2 \ 17 & -6 & -1 \ 30 & -10 & -2 \end{bmatrix}$

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(C) To find the adjoint of matrix $A$,we first find the cofactor of each element of $A$.Let $C_{ij}$ be the cofactor of the element $a_{ij}$.$C_{11} = +((-6)(4) - (5)(0)) = -24$$C_{12} = -((2)(4) - (5)(5)) = -(8 - 25) = 17$$C_{13} = +((2)(0) - (-6)(5)) = 30$$C_{21} = -((-2)(4) - (2)(0)) = -(-8) = 8$$C_{22} = +((1)(4) - (2)(5)) = 4 - 10 = -6$$C_{23} = -((1)(0) - (-2)(5)) = -(0 + 10) = -10$$C_{31} = +((-2)(5) - (2)(-6)) = -10 + 12 = 2$$C_{32} = -((1)(5) - (2)(2)) = -(5 - 4) = -1$$C_{33} = +((1)(-6) - (-2)(2)) = -6 + 4 = -2$The cofactor matrix $C$ is $\begin{bmatrix} -24 & 17 & 30 \ 8 & -6 & -10 \ 2 & -1 & -2 \end{bmatrix}$.The adjoint of $A$ is the transpose of the cofactor matrix,$\operatorname{Adj} A = C^T = \begin{bmatrix} -24 & 8 & 2 \ 17 & -6 & -1 \ 30 & -10 & -2 \end{bmatrix}$.

If $A = \begin{bmatrix} 1 & -2 & 2 \\ 2 & -6 & 5 \\ 5 & 0 & 4 \end{bmatrix}$,then $\operatorname{Adj} A = $

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