If $8 f(x)+6 f\left(\frac{1}{x}\right)=x+5$ and $y=x^2 f(x)$,then $\frac{d y}{d x}$ at $x=-1$ equals

  • A
    $0$
  • B
    $\frac{1}{14}$
  • C
    $\frac{-1}{14}$
  • D
    $1$

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