If $\frac{x^4+24x^2+28}{(x^2+1)^3} = \frac{A}{x^2+1} + \frac{B}{(x^2+1)^2} + \frac{C}{(x^2+1)^3}$,then $A+C=$

  • A
    $12$
  • B
    $10$
  • C
    $9$
  • D
    $6$

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