If $a=\hat{i}+2 \hat{j}+3 \hat{k}$,$b=-\hat{i}+2 \hat{j}+\hat{k}$,$c=\hat{i}+2 \hat{j}-2 \hat{k}$,$n$ is perpendicular to both $a$ and $b$,and $\theta$ is the angle between $c$ and $n$,then $\sin \theta=$

  • A
    $\sqrt{\frac{2}{3}}$
  • B
    $\frac{\sqrt{2}}{3 \sqrt{3}}$
  • C
    $\frac{2}{\sqrt{3}}$
  • D
    $\frac{\sqrt{3}}{2}$

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