If $\alpha, \beta, \gamma$ are the roots of the equation $2x^3+x^2-13x+6=0$,then $\alpha^3+\beta^3+\gamma^3=$

  • A
    $-\frac{161}{8}$
  • B
    $36$
  • C
    $99$
  • D
    $-\frac{151}{8}$

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