If $C_0, C_1, C_2, \ldots, C_8$ are the binomial coefficients in the expansion of $(1+x)^8$,then $\sum_{r=1}^8 r^3 \frac{C_r}{C_{r-1}} =$

  • A
    $540$
  • B
    $336$
  • C
    $105$
  • D
    $270$

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