यदि $\tan \theta + \cot \theta = 2$ है,तो $\sin \theta$ का मान क्या होगा?

  • A
    $\frac{1}{\sqrt{2}}$
  • B
    $\frac{1}{\sqrt{3}}$
  • C
    $\frac{1}{2}$
  • D
    $1$

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एक धनात्मक पूर्णांक $n$ के लिए,मान लीजिए ${f_n}(\theta ) = \left( {\tan \frac{\theta }{2}} \right)(1 + \sec \theta )(1 + \sec 2\theta )(1 + \sec 4\theta ) \dots (1 + \sec {2^n}\theta ).$ तो

योगफल ज्ञात कीजिए: $\sin^2(3^{\circ}) + \sin^2(6^{\circ}) + \sin^2(9^{\circ}) + \dots + \sin^2(84^{\circ}) + \sin^2(87^{\circ}) + \sin^2(90^{\circ})$

समीकरण $\frac{1}{\sin(\frac{\pi}{n})} = \frac{1}{\sin(\frac{2\pi}{n})} + \frac{1}{\sin(\frac{3\pi}{n})}$ को संतुष्ट करने वाला $n > 3$ का धनात्मक पूर्णांक मान है

$\sin ^4 \frac{\pi}{8}+\sin ^4 \frac{2 \pi}{8}+\sin ^4 \frac{3 \pi}{8}+\sin ^4 \frac{4 \pi}{8}+\sin ^4 \frac{5 \pi}{8}+\sin ^4 \frac{6 \pi}{8}+\sin ^4 \frac{7 \pi}{8} = ?$

यदि $\alpha, \beta$ न्यून कोण हैं जैसे कि $\frac{\sin \alpha}{\sin \beta} = \frac{6}{5}$ और $\frac{\cos \alpha}{\cos \beta} = \frac{9}{5 \sqrt{5}}$,तो $\sin \alpha = $

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