If cos theta = -frac{1}{sqrt{2}} and tan thet | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given $\cos 	heta = -\frac{1}{\sqrt{2}}$. Since $\cos 	heta$ is negative,$	heta$ lies in the second or third quadrant. $\cos 	heta = \cos(\pi

Vedclass · Accepted Answer

$(2n + 1)\pi + \frac{\pi}{4}, n = 0, 1, 2, 3 \ldots$

Vedclass · Answer

(B) Given $\cos 	heta = -\frac{1}{\sqrt{2}}$. Since $\cos 	heta$ is negative,$	heta$ lies in the second or third quadrant. $\cos 	heta = \cos(\pi - \frac{\pi}{4}) = \cos \frac{3\pi}{4}$ or $\cos 	heta = \cos(\pi + \frac{\pi}{4}) = \cos \frac{5\pi}{4}$.Given $	an 	heta = 1$. Since $	an 	heta$ is positive,$	heta$ lies in the first or third quadrant. $	an 	heta = 	an \frac{\pi}{4}$ or $	an 	heta = 	an(\pi + \frac{\pi}{4}) = 	an \frac{5\pi}{4}$.The common value satisfying both equations is $	heta = \frac{5\pi}{4}$.The general solution for $	heta$ is $2n\pi + \frac{5\pi}{4}$,which can be written as $2n\pi + \pi + \frac{\pi}{4} = (2n + 1)\pi + \frac{\pi}{4}$ for $n = 0, 1, 2, \ldots$.

If $\cos \theta = -\frac{1}{\sqrt{2}}$ and $\tan \theta = 1$,then the general value of $\theta$ is

Similar Questions

If $\sin \theta = \sqrt{3} \cos \theta$ and $-\pi < \theta < 0$,then $\theta = $

The general value of $\theta$ satisfying $\sin^2 \theta + \sin \theta = 2$ is

The number of values of $x$ for which $\sin 2x + \cos 4x = 2$ is

If $\sin 2\theta = \cos 3\theta$ and $\theta$ is an acute angle,then $\sin \theta$ is equal to

The solutions of $\sin x + \sin 5x = \sin 3x$ in the interval $(0, \frac{\pi}{2})$ are

Vedclass Test Series

Exam Paper Generator

Online Exam Module