If $t$ is a parameter,$A = (a \sec t, b \tan t)$,$B = (-a \tan t, b \sec t)$,and $O = (0, 0)$,then the locus of the centroid of $\triangle OAB$ is:

  • A
    $9xy = ab$
  • B
    $xy = 9ab$
  • C
    $x^2 - 9y^2 = a^2 - b^2$
  • D
    $x^2 - y^2 = \frac{1}{9}(a^2 - b^2)$

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