If $\frac{x^2}{\alpha+3}+\frac{y^2}{2-\alpha}=1$ represents a hyperbola,then $\alpha$ lies in

  • A
    $(-3, 2)$
  • B
    $(-3, \infty)$
  • C
    $(-\infty, -2)$
  • D
    $(-\infty, -3) \cup (2, \infty)$

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