If $\cosh ^{-1}\left(\frac{5}{3}\right)+\sinh ^{-1}\left(\frac{3}{4}\right)=k$, then $e^k=$

  • A
    $\frac{2}{3}$
  • B
    $\frac{3}{2}$
  • C
    $6$
  • D
    $5$

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