If $\log 2=a, \log 3=b, \log 7=c$ and $6^x=7^{x+4}$, then $x$ is equal to:

  • A
    $\frac{4b}{c+a-b}$
  • B
    $\frac{4c}{a+b-c}$
  • C
    $\frac{4c}{c-a-b}$
  • D
    $\frac{4a}{a+b-c}$

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