If a, b, c neq 0 and belong to the set {0, 1, | vedclass

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(D) Given the expression: $\log _{10}\left(\frac{a+10 b+10^2 c}{10^{-4} a+10^{-3} b+10^{-2} c}\right)$ We can simplify the denominator by factoring ou

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$4$

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(D) Given the expression: $\log _{10}\left(\frac{a+10 b+10^2 c}{10^{-4} a+10^{-3} b+10^{-2} c}\right)$ We can simplify the denominator by factoring out $10^{-4}$: $10^{-4} a + 10^{-3} b + 10^{-2} c = 10^{-4}(a + 10b + 10^2c)$ Substituting this back into the expression: $\log _{10}\left(\frac{a+10 b+10^2 c}{10^{-4}(a+10 b+10^2 c)}\right)$ $= \log _{10}\left(\frac{1}{10^{-4}}\right)$ $= \log _{10}(10^4)$ $= 4 \log _{10}(10) = 4(1) = 4$

If $a, b, c \neq 0$ and belong to the set $\{0, 1, 2, 3, \ldots, 9\}$, then $\log _{10}\left(\frac{a+10 b+10^2 c}{10^{-4} a+10^{-3} b+10^{-2} c}\right)$ is equal to

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