If $2 \hat{i}+4 \hat{j}-5 \hat{k}$, $\hat{i}+\hat{j}+\hat{k}$, and $\hat{j}+2 \hat{k}$ are the position vectors of the vertices $A$, $B$, and $C$ of a triangle respectively, then a unit vector along the median drawn through the vertex $A$ is

  • A
    $\frac{1}{\sqrt{174}}(5 \hat{i}+10 \hat{j}-7 \hat{k})$
  • B
    $\frac{1}{\sqrt{214}}(3 \hat{i}+6 \hat{j}-13 \hat{k})$
  • C
    $\frac{1}{\sqrt{66}}(\hat{i}+\hat{j}-8 \hat{k})$
  • D
    $\frac{1}{7}(3 \hat{i}+6 \hat{j}-2 \hat{k})$

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