If $D, E$ and $F$ are respectively the mid-points of $AB, AC$ and $BC$ in $\triangle ABC$, then $\overrightarrow{BE} + \overrightarrow{AF}$ is equal to :

  • A
    $\overrightarrow{DC}$
  • B
    $\frac{1}{2} \overrightarrow{BF}$
  • C
    $2 \overrightarrow{BF}$
  • D
    $\frac{3}{2} \overrightarrow{BF}$

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