If $\theta$ is the angle between the vectors $2 \hat{i}-\hat{j}+2 \hat{k}$ and $a \hat{i}+4 \hat{j}+b \hat{k}$ and $\cos \theta=\frac{2}{3}$, then $2(a+b+3)=$

  • A
    $a^2+b^2$
  • B
    $a^2$
  • C
    $b^2$
  • D
    $ab$

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