If $X$ is a Poisson variate such that $\frac{5}{3} k = P(X=2) = P(X=3)$, then $P(X=5) =$

  • A
    $k$
  • B
    $\frac{1}{4} k$
  • C
    $\frac{1}{2} k$
  • D
    $\frac{3}{4} k$

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