If (x, y) in R and x, y neq 0,and the functio | vedclass

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(A) The function is defined as $f: (\mathbb{R} \setminus \{0\}) 	imes (\mathbb{R} \setminus \{0\}) 	o \mathbb{R}$ given by $f(x, y) = \frac{x}{y}$.F

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Surjection

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(A) The function is defined as $f: (\mathbb{R} \setminus \{0\}) 	imes (\mathbb{R} \setminus \{0\}) 	o \mathbb{R}$ given by $f(x, y) = \frac{x}{y}$.For any real number $c \in \mathbb{R}$,we can choose $x = c$ and $y = 1$. Then $f(c, 1) = \frac{c}{1} = c$. Since for every $c$ in the codomain there exists at least one pair $(x, y)$ in the domain such that $f(x, y) = c$,the function is surjective (onto).However,the function is not one-one because $f(2, 1) = 2$ and $f(4, 2) = 2$. Since $f(2, 1) = f(4, 2)$ but $(2, 1) 
eq (4, 2)$,it is not injective.Since it is not injective,it cannot be a bijection.Therefore,the correct classification is a surjection.

If $(x, y) \in R$ and $x, y \neq 0$,and the function $f(x, y) = \frac{x}{y}$,then this function is a/an:

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