If A=begin{bmatrix} 1 & 1 0 & i end{bmatrix} | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given $A = \begin{bmatrix} 1 & 1 \ 0 & i \end{bmatrix}$.Calculate the powers of $A$:$A^2 = \begin{bmatrix} 1 & 1 \ 0 & i \end{bmatrix} \begin{bm

Vedclass · Accepted Answer

$0$

Vedclass · Answer

(B) Given $A = \begin{bmatrix} 1 & 1 \ 0 & i \end{bmatrix}$.Calculate the powers of $A$:$A^2 = \begin{bmatrix} 1 & 1 \ 0 & i \end{bmatrix} \begin{bmatrix} 1 & 1 \ 0 & i \end{bmatrix} = \begin{bmatrix} 1 & 1+i \ 0 & i^2 \end{bmatrix} = \begin{bmatrix} 1 & 1+i \ 0 & -1 \end{bmatrix}$.$A^3 = A^2 	imes A = \begin{bmatrix} 1 & 1+i \ 0 & -1 \end{bmatrix} \begin{bmatrix} 1 & 1 \ 0 & i \end{bmatrix} = \begin{bmatrix} 1 & 1+i+i \ 0 & -i \end{bmatrix} = \begin{bmatrix} 1 & 1+2i \ 0 & -i \end{bmatrix}$.Wait, let us re-evaluate $A^4$:$A^4 = A^2 	imes A^2 = \begin{bmatrix} 1 & 1+i \ 0 & -1 \end{bmatrix} \begin{bmatrix} 1 & 1+i \ 0 & -1 \end{bmatrix} = \begin{bmatrix} 1 & 1+i-1-i \ 0 & 1 \end{bmatrix} = \begin{bmatrix} 1 & 0 \ 0 & 1 \end{bmatrix} = I$.Since $A^4 = I$, we have $A^{2018} = A^{2016} 	imes A^2 = (A^4)^{504} 	imes A^2 = I^{504} 	imes A^2 = A^2$.Thus, $A^{2018} = \begin{bmatrix} 1 & 1+i \ 0 & -1 \end{bmatrix}$.Comparing with $\begin{bmatrix} a & b \ c & d \end{bmatrix}$, we get $a=1$ and $d=-1$.Therefore, $a+d = 1 + (-1) = 0$.

If $A=\begin{bmatrix} 1 & 1 \\ 0 & i \end{bmatrix}$ and $A^{2018}=\begin{bmatrix} a & b \\ c & d \end{bmatrix}$, then $(a+d)$ equals

Similar Questions

If $\begin{bmatrix} 2 & 3 & 4 \end{bmatrix} \begin{bmatrix} 1 & x & 3 \\ 2 & 4 & 5 \\ 3 & 2 & x \end{bmatrix} \begin{bmatrix} x \\ 2 \\ 0 \end{bmatrix} = O$,then $x = $ . . . . . .

If $A = \begin{bmatrix} 1 & -2 & 3 \\ -4 & 2 & 5 \end{bmatrix}$ and $B = \begin{bmatrix} 2 & 3 \\ 4 & 5 \\ 2 & 1 \end{bmatrix}$,then find $AB$ and $BA$. Show that $AB \neq BA$.

Express the following matrix as the sum of a symmetric and a skew-symmetric matrix: $\left[\begin{array}{cc}3 & 5 \\ 1 & -1\end{array}\right]$

If $A = \begin{bmatrix} 1 & 0 & 0 \\ 2 & 1 & 0 \\ -3 & 2 & 1 \end{bmatrix}$ and $B = \begin{bmatrix} 1 & 0 & 0 \\ -2 & 1 & 0 \\ 7 & -2 & 1 \end{bmatrix}$,then $AB$ equals

If $A = \begin{bmatrix} 1 & 1 \\ 0 & 1 \end{bmatrix}$ and $B = \begin{bmatrix} x & y \\ 0 & x \end{bmatrix}$,then $AB = BA$ (given $B \neq I$). Which of the following matrices $B$ satisfies this condition?

Vedclass Test Series

Exam Paper Generator

Online Exam Module