If $f(x) = \begin{cases} \frac{x^2 - 9}{x - 3}, & \text{if } x \neq 3 \\ 2x + k, & \text{otherwise} \end{cases}$ is continuous at $x = 3$,then $k = $

  • A
    $3$
  • B
    $0$
  • C
    $-6$
  • D
    $1/6$

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