If $y = \sin^{-1}(\sqrt{x})$,then $\frac{dy}{dx} = $

  • A
    $\frac{2}{\sqrt{x}\sqrt{1-x}}$
  • B
    $-\frac{2}{\sqrt{x}\sqrt{1-x}}$
  • C
    $\frac{1}{2\sqrt{x}\sqrt{1-x}}$
  • D
    $\frac{1}{\sqrt{1-x}}$

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