If $m$ rupee coins and $n$ ten paise coins are placed in a line,then the probability that the extreme coins are ten paise coins is

  • A
    $^{m + n}C_m / n^m$
  • B
    $\frac{n(n - 1)}{(m + n)(m + n - 1)}$
  • C
    $^{m + n}P_m / m^n$
  • D
    $^{m + n}P_n / n^m$

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