If $A$ and $B$ are two events such that $P(A \cup B) = \frac{5}{6}$,$P(A \cap B) = \frac{1}{3}$ and $P(\bar{B}) = \frac{1}{3}$,then $P(A) = $

  • A
    $\frac{1}{4}$
  • B
    $\frac{1}{3}$
  • C
    $\frac{1}{2}$
  • D
    $\frac{2}{3}$

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