In a certain population,10% of the people are | vedclass

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(C) Let $R$ be the event that a person is rich and $F$ be the event that a person is famous.Given: $P(R) = 10\% = 0.1$,$P(F) = 5\% = 0.05$,and $P(R \c

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$0.09$

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(C) Let $R$ be the event that a person is rich and $F$ be the event that a person is famous.Given: $P(R) = 10\% = 0.1$,$P(F) = 5\% = 0.05$,and $P(R \cap F) = 3\% = 0.03$.We need to find the probability that a person is either rich or famous but not both,which is given by the symmetric difference $P(R \Delta F) = P(R \cup F) - P(R \cap F)$.Alternatively,$P(R \Delta F) = P(R) + P(F) - 2P(R \cap F)$.Substituting the values:$P(R \Delta F) = 0.1 + 0.05 - 2(0.03)$$P(R \Delta F) = 0.15 - 0.06 = 0.09$.

In a certain population,$10\%$ of the people are rich,$5\%$ are famous,and $3\%$ are both rich and famous. The probability that a person picked at random from the population is either famous or rich but not both,is equal to

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