If $g$ is the inverse of a function $f$ and $f'(x) = \frac{1}{1 + x^5}$,then $g'(x)$ is equal to:
- A$1 + (g(x))^5$
- B$\frac{1}{1 + (g(x))^5}$
- C$1 + x^5$
- D$5x^4$
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View SolutionConsider $f: \{1, 2, 3\} \rightarrow \{a, b, c\}$ given by $f(1) = a, f(2) = b$ and $f(3) = c$. Find $f^{-1}$ and show that $(f^{-1})^{-1} = f$.
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