If f(x) is an odd periodic function with peri | vedclass

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(A) Given that $f(x)$ is an odd function,we have $f(-x) = -f(x)$.For any odd function,$f(0) = -f(0)$,which implies $2f(0) = 0$,so $f(0) = 0$.Given tha

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(A) Given that $f(x)$ is an odd function,we have $f(-x) = -f(x)$.For any odd function,$f(0) = -f(0)$,which implies $2f(0) = 0$,so $f(0) = 0$.Given that $f(x)$ is a periodic function with period $T = 1$,we have $f(x + 1) = f(x)$ for all $x$.By the property of periodicity,$f(x + nT) = f(x)$ for any integer $n$.Therefore,$f(2) = f(0 + 2 	imes 1) = f(0)$.Since $f(0) = 0$,it follows that $f(2) = 0$.

If $f(x)$ is an odd periodic function with period $1$,then $f(2)$ is equal to:

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