यदि $\frac{\sec 8\theta - 1}{\sec 4\theta - 1} = \frac{a + b \tan^2 2\theta}{1 + c \tan^2 2\theta + d \tan^4 2\theta}$ (जहाँ $\theta \neq \frac{n\pi}{16}, n \in I$),तो $(a - b + c - d)$ का मान ज्ञात कीजिए।
- A$0$
- B$1$
- C$7$
- D$13$
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$\sqrt{2+\sqrt{2+2 \cos 4 \theta}} = $
$\tan 3A - \tan 2A - \tan A = $
Easy
View Solution$\frac{\tan x}{\tan 3x}$ का मान,जब भी परिभाषित हो,कभी भी किसके बीच नहीं होता है?
DifficultIIT 1992
View Solutionयदि $\cos \theta = \frac{-3}{5}$ और $\pi < \theta < \frac{3 \pi}{2}$ है,तो $\tan \left(\frac{\theta}{2}\right) = $
यदि $\frac{\tan 3A}{\tan A} = a$ है,तो $\frac{\sin 3A}{\sin A}$ का मान ज्ञात कीजिए।
DifficultAP EAMCET 2005
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