If a circle $C$ passing through $(4, 0)$ touches the circle $x^2 + y^2 + 4x - 6y - 12 = 0$ externally at a point $(1, -1),$ then the radius of the circle $C$ is

  • A
    $5$
  • B
    $2\sqrt{5}$
  • C
    $4$
  • D
    $\sqrt{57}$

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