If a line intercepted between the coordinate axes is trisected at a point $A(4, 3)$,which is nearer to the $x$-axis,then its equation is

  • A
    $4x - 3y = 7$
  • B
    $3x + 2y = 18$
  • C
    $3x + 8y = 36$
  • D
    $x + 3y = 13$

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$A$ straight line cuts off the intercepts $OA = a$ and $OB = b$ on the positive directions of $x$-axis and $y$-axis respectively. If the perpendicular from origin $O$ to this line makes an angle of $\frac{\pi}{6}$ with the positive direction of $y$-axis and the area of $\triangle OAB$ is $\frac{98}{3} \sqrt{3}$,then $a^2 - b^2$ is equal to:

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