If a sum of money at simple interest doubles | vedclass

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(C) Let the principal be $P$. Given that the amount becomes $2P$ in $6$ years,the Simple Interest $(SI)$ is $Amount - Principal = 2P - P = P$. Using t

Vedclass · Accepted Answer

$18$

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(C) Let the principal be $P$. Given that the amount becomes $2P$ in $6$ years,the Simple Interest $(SI)$ is $Amount - Principal = 2P - P = P$. Using the formula $SI = \frac{P 	imes R 	imes T}{100}$,we have $P = \frac{P 	imes R 	imes 6}{100}$. Solving for $R$,we get $R = \frac{100}{6} = \frac{50}{3} \%$ per annum. Now,we want the amount to become $4P$. This means the required $SI = 4P - P = 3P$. Using the formula again: $3P = \frac{P 	imes (50/3) 	imes T}{100}$. $3 = \frac{50 	imes T}{300} \Rightarrow 3 = \frac{T}{6} \Rightarrow T = 18$ years.

If a sum of money at simple interest doubles itself in $6$ years,it will become four times in how many years?

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