If a tetraploid plant contains 48 chromosomes | vedclass

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(B) The nucellus is a diploid $(2n)$ tissue in the ovule,but in a tetraploid plant,the somatic cells are $4n$. Given that the tetraploid plant has $4n

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$24$ and $24$

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(B) The nucellus is a diploid $(2n)$ tissue in the ovule,but in a tetraploid plant,the somatic cells are $4n$. Given that the tetraploid plant has $4n = 48$ chromosomes in its nucellus,the haploid number $(n)$ is $48 / 4 = 12$. The egg cell and synergids are part of the embryo sac (gametophyte) and are haploid $(n)$. Therefore,the number of chromosomes in the egg cell is $n = 12$ and in a synergid is $n = 12$. Wait,re-evaluating the ploidy: If the plant is tetraploid $(4n)$,the gametes produced by meiosis are diploid $(2n)$. Thus,$4n = 48$,so $2n = 24$. Both the egg cell and synergids are haploid relative to the sporophyte,but since the sporophyte is $4n$,the gametophyte cells are $2n$. Therefore,both the egg cell and the synergid contain $24$ chromosomes.

If a tetraploid plant contains $48$ chromosomes in its nucellus,then what is the number of chromosomes in the egg cell and in a synergid,respectively?

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