If an electron and a positron annihilate,then the energy released is

Nuclear fission is possible because the binding energy per nucleon ...

From the given data,the amount of energy required to break the nucleus of aluminium ${ }_{13}^{27} {Al}$ is $x \times 10^{-3} {J}$.
Mass of neutron $= 1.00866 \, {u}$
Mass of proton $= 1.00726 \, {u}$
Mass of aluminium nucleus $= 26.98154 \, {u}$
(Assume $1 \, {u}$ corresponds to $1 \, {J}$ of energy for the purpose of this calculation)
(Round off to the nearest integer)

The energy in $MeV$ released due to the complete transformation of $1\, kg$ of mass into energy is $(c = 3 \times 10^8\, m/s)$:

Assume the graph of specific binding energy versus mass number is as shown in the figure. Using this graph,select the correct choice from the following.

Which element has the maximum binding energy per nucleon? Write down its value.