If any tangent to the ellipse frac{x^2}{a^2} | vedclass

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(B) The equation of the tangent at point $(a \cos 	heta, b \sin 	heta)$ to the ellipse $\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1$ is given by $\frac{x

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(B) The equation of the tangent at point $(a \cos 	heta, b \sin 	heta)$ to the ellipse $\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1$ is given by $\frac{x \cos 	heta}{a} + \frac{y \sin 	heta}{b} = 1$.This can be rewritten in intercept form as $\frac{x}{(a / \cos 	heta)} + \frac{y}{(b / \sin 	heta)} = 1$.Comparing this with the intercept form $\frac{x}{h} + \frac{y}{k} = 1$,we get $h = \frac{a}{\cos 	heta}$ and $k = \frac{b}{\sin 	heta}$.Therefore,$\frac{a^2}{h^2} + \frac{b^2}{k^2} = \frac{a^2}{(a / \cos 	heta)^2} + \frac{b^2}{(b / \sin 	heta)^2} = \cos^2 	heta + \sin^2 	heta = 1$.

If any tangent to the ellipse $\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1$ cuts off intercepts of length $h$ and $k$ on the axes,then $\frac{a^2}{h^2} + \frac{b^2}{k^2} = $

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