If the discriminant D = 0,then the roots of t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The quadratic formula for the roots of the equation $ax^2 + bx + c = 0$ is given by $x = \frac{-b \pm \sqrt{D}}{2a}$,where $D = b^2 - 4ac$ is the

Vedclass · Accepted Answer

$-\frac{b}{2a}$

Vedclass · Answer

(B) The quadratic formula for the roots of the equation $ax^2 + bx + c = 0$ is given by $x = \frac{-b \pm \sqrt{D}}{2a}$,where $D = b^2 - 4ac$ is the discriminant.Given that the discriminant $D = 0$,we substitute this into the quadratic formula:$x = \frac{-b \pm \sqrt{0}}{2a}$$x = \frac{-b \pm 0}{2a}$$x = -\frac{b}{2a}$Therefore,when $D = 0$,the quadratic equation has two equal real roots,each equal to $-\frac{b}{2a}$.

If the discriminant $D = 0$,then the roots of the quadratic equation $ax^2 + bx + c = 0$ are ..... .

Similar Questions

State whether the quadratic equation $(x-\sqrt{2})^{2}-2(x+1)=0$ has two distinct real roots. Justify your answer.

Find the discriminant of the following quadratic equation: $x^{2}-7x+10=0$

Examine whether the following equation is quadratic or not: $(2x + 1)(3x + 2) = 6(x - 1)(x - 2)$

If one of the roots of quadratic equation $x^{2}+4x+m=0$ is $2$,then the other root is .... .

If both the roots of a quadratic equation $kx^{2} + 4x + 1 = 0$ are equal,then $k = \ldots$

Vedclass Test Series

Exam Paper Generator

Online Exam Module