(C) When equal volumes are mixed,the concentration of each species is halved. The reaction is $AB_2 + 2XY \rightarrow AY_2 + 2XB$. For precipitation t

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

$2.0 \times 10^{-2} \ M \ AB_2, 2.0 \times 10^{-2} \ M \ XY$

(C) When equal volumes are mixed,the concentration of each species is halved. The reaction is $AB_2 + 2XY \rightarrow AY_2 + 2XB$. For precipitation to occur,the ionic product $Q_{sp}$ must be greater than $K_{sp}$. $Q_{sp} = [A^{2+}][Y^-]^2$. For option $C$: $[A^{2+}] = (2.0 \times 10^{-2} / 2) = 1.0 \times 10^{-2} \ M$ and $[Y^-] = (2.0 \times 10^{-2} / 2) = 1.0 \times 10^{-2} \ M$. $Q_{sp} = (1.0 \times 10^{-2}) \times (1.0 \times 10^{-2})^2 = 1.0 \times 10^{-6}$. Since $1.0 \times 10^{-6} > 5.2 \times 10^{-7}$,a precipitate will form.

Class 11 Chemistry 6-2.Equilibrium-II (Ionic Equilibrium)Solubility product

Medium

If equal volumes of $AB_2$ and $XY$ (both are salts) aqueous solutions are mixed,which of the following combinations will give a precipitate of $AY_2$ at $300 \ K$? (Given $K_{sp}$ (at $300 \ K$) for $AY_2 = 5.2 \times 10^{-7}$)

JEE MAIN 2025 All JEE MAIN

A
$3.6 \times 10^{-3} \ M \ AB_2, 5.0 \times 10^{-4} \ M \ XY$
B
$2.0 \times 10^{-4} \ M \ AB_2, 0.8 \times 10^{-3} \ M \ XY$
C
$2.0 \times 10^{-2} \ M \ AB_2, 2.0 \times 10^{-2} \ M \ XY$
D
$1.5 \times 10^{-4} \ M \ AB_2, 1.5 \times 10^{-3} \ M \ XY$

Explore More

Browse All

Question Bank

All Subjects

Class 11 Questions

Class 11

Chemistry Questions

Chapter

6-2.Equilibrium-II (Ionic Equilibrium)

Subtopic

Solubility product

Previous Year

JEE MAIN 2025 Paper All JEE MAIN years →

The solubility product $(K_{sp})$ values of $CuS$,$Ag_2S$,and $HgS$ are $10^{-31}$,$10^{-44}$,and $10^{-54}$ respectively. The solubilities of these sulphides are in the order:

MediumAIPMT 1997

View Solution

$A$ $1.0 \ L$ of aqueous solution contains $1 \times 10^{-8} \ M \ NaBr$,$1 \times 10^{-8} \ M \ NaCl$ and $1 \times 10^{-8} \ M \ NaI$. To this solution,$1 \times 10^{-10} \ M$ aqueous $AgNO_3$ solution is added dropwise. The order of precipitation of $AgX$ $(X = Cl, Br, I)$ is:
$(K_{sp}(AgCl) = 1.8 \times 10^{-10}; K_{sp}(AgBr) = 5 \times 10^{-13}; K_{sp}(AgI) = 8.3 \times 10^{-17})$

DifficultAP EAMCET 2022

View Solution

For which sparingly soluble salt is the relationship between $K_{sp}$ and $S$ (solubility) given by $S = (K_{sp} / 4)^{1/3}$?

Medium

View Solution

Which one of the following is most soluble?

DifficultAIPMT 1994

View Solution

$MY$ and $NY_3$,two nearly insoluble salts,have the same $K_{sp}$ values of $6.2 \times 10^{-13}$ at room temperature. Which statement would be true in regard to $MY$ and $NY_3$?

DifficultNEET 2016

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

If equal volumes of $AB_2$ and $XY$ (both are salts) aqueous solutions are mixed,which of the following combinations will give a precipitate of $AY_2$ at $300 \ K$? (Given $K_{sp}$ (at $300 \ K$) for $AY_2 = 5.2 \times 10^{-7}$)

Similar Questions

The solubility product $(K_{sp})$ values of $CuS$,$Ag_2S$,and $HgS$ are $10^{-31}$,$10^{-44}$,and $10^{-54}$ respectively. The solubilities of these sulphides are in the order:

For which sparingly soluble salt is the relationship between $K_{sp}$ and $S$ (solubility) given by $S = (K_{sp} / 4)^{1/3}$?

Which one of the following is most soluble?

$MY$ and $NY_3$,two nearly insoluble salts,have the same $K_{sp}$ values of $6.2 \times 10^{-13}$ at room temperature. Which statement would be true in regard to $MY$ and $NY_3$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module