If fringe width is 0.4 ,mm, the distance betw | vedclass

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(A) The fringe width is given by $\beta = \frac{\lambda D}{d} = 0.4 \,mm$.The position of the $n_{1}$-th bright fringe from the central maximum is giv

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(A) The fringe width is given by $\beta = \frac{\lambda D}{d} = 0.4 \,mm$.The position of the $n_{1}$-th bright fringe from the central maximum is given by $x_{n_1} = n_1 \beta$.For the fifth bright fringe $(n_1 = 5)$:$x_5 = 5 \beta = 5 	imes 0.4 \,mm = 2.0 \,mm$.The position of the $n_2$-th dark fringe from the central maximum is given by $x_{n_2} = (n_2 - 0.5) \beta$.For the third dark fringe $(n_2 = 3)$:$x_3 = (3 - 0.5) \beta = 2.5 \beta = 2.5 	imes 0.4 \,mm = 1.0 \,mm$.The distance between the fifth bright and third dark band on the same side is:$\Delta x = x_5 - x_3 = 2.0 \,mm - 1.0 \,mm = 1.0 \,mm$.

If fringe width is $0.4 \,mm$, the distance between the fifth bright and third dark band on the same side is: (in $\,mm$)

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