(C) Using the Law of Cosines: $a^2 = b^2 + c^2 - 2bc \cos A$Given $b = 2$,$c = \sqrt{3}$,and $\angle A = \frac{\pi}{6}$:$a^2 = (2)^2 + (\sqrt{3})^2 -

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(C) Using the Law of Cosines: $a^2 = b^2 + c^2 - 2bc \cos A$Given $b = 2$,$c = \sqrt{3}$,and $\angle A = \frac{\pi}{6}$:$a^2 = (2)^2 + (\sqrt{3})^2 - 2(2)(\sqrt{3}) \cos(\frac{\pi}{6})$$a^2 = 4 + 3 - 4\sqrt{3} \cdot \frac{\sqrt{3}}{2}$$a^2 = 7 - 6 = 1$$a = 1$Using the Sine Rule: $R = \frac{a}{2 \sin A}$$R = \frac{1}{2 \sin(\frac{\pi}{6})} = \frac{1}{2 \cdot (1/2)} = 1$

Class 11 Mathematics Trigonometrical Equations Relation between sides and angles, Solutions of triangles

If in a $\Delta ABC$,$b = 2$,$c = \sqrt{3}$,$\angle A = \frac{\pi}{6}$,then $R = $?

A
$1/2$
B
$2$
C
$1$
D
None

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Trigonometrical Equations

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Relation between sides and angles, Solutions of triangles

In a $\Delta ABC,$ if $b = 20, c = 21$ and $\sin A = 3/5$,then $a = $

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In a triangle $ABC$,if $b + c = 2a$ and $\angle A = 60^\circ$,then $\Delta ABC$ is

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If in a triangle $ABC,$ $(s - a)(s - b) = s(s - c)$,then angle $C$ is equal to.....$^o$

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In $\Delta ABC, a(b\cos C - c\cos B) = $

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In $\triangle ABC$, with usual notations, if the sides $a, b$ and $c$ are in the ratio $18 : 17 : 7$, then $\cot \frac{A}{2} : \cot \frac{B}{2} : \cot \frac{C}{2} = $

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If in a $\Delta ABC$,$b = 2$,$c = \sqrt{3}$,$\angle A = \frac{\pi}{6}$,then $R = $?

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In a $\Delta ABC,$ if $b = 20, c = 21$ and $\sin A = 3/5$,then $a = $

In a triangle $ABC$,if $b + c = 2a$ and $\angle A = 60^\circ$,then $\Delta ABC$ is

If in a triangle $ABC,$ $(s - a)(s - b) = s(s - c)$,then angle $C$ is equal to.....$^o$

In $\Delta ABC, a(b\cos C - c\cos B) = $

In $\triangle ABC$, with usual notations, if the sides $a, b$ and $c$ are in the ratio $18 : 17 : 7$, then $\cot \frac{A}{2} : \cot \frac{B}{2} : \cot \frac{C}{2} = $

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