In $\triangle ABC$, with usual notations, if the sides $a, b$ and $c$ are in the ratio $18 : 17 : 7$, then $\cot \frac{A}{2} : \cot \frac{B}{2} : \cot \frac{C}{2} = $

  • A
    $3 : 5 : 7$
  • B
    $4 : 5 : 6$
  • C
    $3 : 4 : 5$
  • D
    $5 : 6 : 7$

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