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(D) The resultant intensity $I$ of two interfering waves with intensities $I_1$ and $I_2$ and phase difference $\phi$ is given by the formula:$I = I_1

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$I = 2I_0 (1 + \cos \phi)$

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(D) The resultant intensity $I$ of two interfering waves with intensities $I_1$ and $I_2$ and phase difference $\phi$ is given by the formula:$I = I_1 + I_2 + 2 \sqrt{I_1 I_2} \cos \phi$Given that the intensity of each wave is $I_0$,we have $I_1 = I_0$ and $I_2 = I_0$.Substituting these values into the formula:$I = I_0 + I_0 + 2 \sqrt{I_0 \cdot I_0} \cos \phi$$I = 2I_0 + 2I_0 \cos \phi$$I = 2I_0 (1 + \cos \phi)$Thus,the correct option is $D$.

If the intensity of each wave in the observed interference pattern in Young's double slit experiment is $I_0$,then for some point $P$ where the phase difference is $\phi$,the resultant intensity $I$ will be:

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