If isobutane and n-butane are present in a ga | vedclass

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(A) Isobutane and $n$-butane are isomers with the same molecular formula,$C_4H_{10}$.The balanced chemical equation for the combustion of $C_4H_{10}$

Vedclass · Accepted Answer

$17.9$

Vedclass · Answer

(A) Isobutane and $n$-butane are isomers with the same molecular formula,$C_4H_{10}$.The balanced chemical equation for the combustion of $C_4H_{10}$ is:$C_4H_{10} + \frac{13}{2} O_2 	o 4CO_2 + 5H_2O$According to the stoichiometry,$1 \ mol$ of $C_4H_{10}$ $(58 \ g)$ requires $\frac{13}{2} \ mol$ of $O_2$ $(6.5 	imes 32 = 208 \ g)$.For $5 \ kg$ $(5000 \ g)$ of $C_4H_{10}$,the mass of $O_2$ required is:$	ext{Mass of } O_2 = \frac{5000 \ g 	imes 208 \ g}{58 \ g} \approx 17931 \ g = 17.93 \ kg$.Thus,the required amount is approximately $17.9 \ kg$.

If isobutane and $n$-butane are present in a gas,then how much oxygen should be required for the complete combustion of $5 \ kg$ of this gas?

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