If lines $\frac{2x-4}{\lambda}=\frac{y-1}{2}=\frac{z-3}{1}$ and $\frac{x-1}{1}=\frac{3y-1}{\lambda}=\frac{z-2}{1}$ are perpendicular to each other,then $\lambda = \ldots$.

  • A
    $7$
  • B
    $-\frac{7}{6}$
  • C
    $6$
  • D
    $-\frac{6}{7}$

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