If momentum is increased by 20 %, then kineti | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The relationship between kinetic energy $K$ and momentum $P$ is given by $K = \frac{P^2}{2m}$.Let the initial momentum be $P$ and the initial kine

Vedclass · Accepted Answer

$44$

Vedclass · Answer

(B) The relationship between kinetic energy $K$ and momentum $P$ is given by $K = \frac{P^2}{2m}$.Let the initial momentum be $P$ and the initial kinetic energy be $K = \frac{P^2}{2m}$.If the momentum is increased by $20 \%$, the new momentum $P'$ becomes $P' = P + 0.20P = 1.2P$.The new kinetic energy $K'$ is given by $K' = \frac{(P')^2}{2m} = \frac{(1.2P)^2}{2m} = \frac{1.44P^2}{2m}$.Substituting $K = \frac{P^2}{2m}$, we get $K' = 1.44K$.The percentage increase in kinetic energy is given by $\frac{K' - K}{K} 	imes 100 \% = \frac{1.44K - K}{K} 	imes 100 \% = 0.44 	imes 100 \% = 44 \%$.

If momentum is increased by $20 \%$, then kinetic energy increases by (in $\%$)

Similar Questions

$A$ particle is initially at rest on a frictionless horizontal surface. $A$ force of constant magnitude and direction is applied to it. The graph shows the work done $(W)$ on the particle versus its speed $(v)$. If no other horizontal forces act on the particle,what should the graph look like?

The kinetic energy of a particle increases by $300\%$. The percentage increase in its momentum is ........ $\%$.

If an object has no kinetic energy,it cannot have momentum. Do you agree?

Two bodies of mass $4 \,g$ and $25 \,g$ are moving with equal kinetic energies. The ratio of the magnitude of their linear momentum is:

In the Olympic games,an athlete covers a distance of $100 \ m$ in $10 \ s$. The estimated range of their kinetic energy is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module