If one ticket is selected at random from $30$ tickets,each with a distinct number from $1$ to $30$,then the probability that the number on the selected ticket is a multiple of $3$ or $5$ is

  • A
    $\frac{14}{31}$
  • B
    $\frac{7}{30}$
  • C
    $\frac{14}{15}$
  • D
    $\frac{7}{15}$

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