(B) Given the quadratic equation: $x(x+1)-6=0$Expanding the equation: $x^{2}+x-6=0$To find the roots,we factorize the quadratic expression:$x^{2}+3x-2

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(B) Given the quadratic equation: $x(x+1)-6=0$Expanding the equation: $x^{2}+x-6=0$To find the roots,we factorize the quadratic expression:$x^{2}+3x-2x-6=0$$x(x+3)-2(x+3)=0$$(x+3)(x-2)=0$Setting each factor to zero:$x+3=0 \implies x=-3$$x-2=0 \implies x=2$Therefore,the roots are $-3$ and $2$.

Class 10 Mathematics Quadratic Equations Mix Examples - Quadratic Equations

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If the roots of the quadratic equation $x(x+1)-6=0$ are

A
$3$ and $-2$
B
$-3$ and $2$
C
$3$ and $2$
D
$-3$ and $-2$

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State whether the quadratic equation $(x+1)(x-2)+x=0$ has two distinct real roots. Justify your answer.

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Find the roots of the following quadratic equation by the factorisation method:
$21 x^{2}-2 x+\frac{1}{21}=0$

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The value of discriminant $D$ for the equation $(3x - 14)^2 = 0$ is ........

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Solve the following equation using the method of factorization and write its solution set: $\frac{x}{x-1} + \frac{x-1}{x} = \frac{25}{12}$

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Solve the following equation by using the general formula,if the equation has a solution in $R$: $5x^{2} + 12x + 10 = 0$.

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If the roots of the quadratic equation $x(x+1)-6=0$ are

Similar Questions

State whether the quadratic equation $(x+1)(x-2)+x=0$ has two distinct real roots. Justify your answer.

Find the roots of the following quadratic equation by the factorisation method:$21 x^{2}-2 x+\frac{1}{21}=0$

The value of discriminant $D$ for the equation $(3x - 14)^2 = 0$ is ........

Solve the following equation using the method of factorization and write its solution set: $\frac{x}{x-1} + \frac{x-1}{x} = \frac{25}{12}$

Solve the following equation by using the general formula,if the equation has a solution in $R$: $5x^{2} + 12x + 10 = 0$.

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Find the roots of the following quadratic equation by the factorisation method:
$21 x^{2}-2 x+\frac{1}{21}=0$