If the 2^{text{nd}} term of an AP is 13 and t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given,the $2^{	ext{nd}}$ term $a_2 = 13$ and the $5^{	ext{th}}$ term $a_5 = 25$.Using the formula for the $n^{	ext{th}}$ term of an $AP$,$a_n =

Vedclass · Accepted Answer

$33$

Vedclass · Answer

(A) Given,the $2^{	ext{nd}}$ term $a_2 = 13$ and the $5^{	ext{th}}$ term $a_5 = 25$.Using the formula for the $n^{	ext{th}}$ term of an $AP$,$a_n = a + (n - 1)d$,we have:$a + d = 13$ .....$(i)$$a + 4d = 25$ .....$(ii)$Subtracting equation $(i)$ from equation $(ii)$:$(a + 4d) - (a + d) = 25 - 13$$3d = 12$$d = 4$Substituting $d = 4$ into equation $(i)$:$a + 4 = 13$$a = 9$Now,finding the $7^{	ext{th}}$ term $a_7$:$a_7 = a + (7 - 1)d$$a_7 = 9 + 6(4)$$a_7 = 9 + 24 = 33$Thus,the $7^{	ext{th}}$ term is $33$.

If the $2^{\text{nd}}$ term of an $AP$ is $13$ and the $5^{\text{th}}$ term is $25$,what is its $7^{\text{th}}$ term?

Similar Questions

The sixth term of an $A.P.$ is $19$ and its seventeenth term is $41$. Find the $50^{th}$ term of the $A.P.$

Which term of the $AP: 21, 42, 63, 84, \ldots$ is $210$?

Find the sum of the first $25$ terms of the $A.P.$ $3, \frac{9}{2}, 6, \frac{15}{2}, \ldots$

For each of the following $A.P.s$,find the $n^{th}$ term: $10.5, 11.7, 12.9, 14.1, \dots$

The $n^{th}$ term of an $A.P.$ is denoted by:

Vedclass Test Series

Exam Paper Generator

Online Exam Module