If the K_b value in the hydrolysis reaction B | vedclass

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(C) The hydrolysis reaction for the cation $B^{+}$ is given by: $B^{+} + H_2O \rightleftharpoons BOH + H^{+}$.For the hydrolysis of a salt of a weak b

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$1.0 	imes 10^{-8}$

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(C) The hydrolysis reaction for the cation $B^{+}$ is given by: $B^{+} + H_2O ightleftharpoons BOH + H^{+}$.For the hydrolysis of a salt of a weak base and a strong acid,the hydrolysis constant $K_H$ is related to the dissociation constant of the base $K_b$ and the ionic product of water $K_w$ by the formula: $K_H = \frac{K_w}{K_b}$.Given $K_w = 1.0 	imes 10^{-14}$ and $K_b = 1.0 	imes 10^{-6}$.Substituting the values: $K_H = \frac{1.0 	imes 10^{-14}}{1.0 	imes 10^{-6}} = 1.0 	imes 10^{-8}$.

If the $K_b$ value in the hydrolysis reaction $B^{+} + H_2O \rightleftharpoons BOH + H^{+}$ is $1.0 \times 10^{-6}$,then the hydrolysis constant of the salt would be

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