If the angle of minimum deviation produced by | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) For an equilateral prism, the angle of the prism $A = 60^{\circ}$.Given that the angle of minimum deviation $\delta_m = A = 60^{\circ}$.The formul

Vedclass · Accepted Answer

$1.732$

Vedclass · Answer

(C) For an equilateral prism, the angle of the prism $A = 60^{\circ}$.Given that the angle of minimum deviation $\delta_m = A = 60^{\circ}$.The formula for the refractive index $n$ of a prism is given by $n = \frac{\sin((A + \delta_m) / 2)}{\sin(A / 2)}$.Substituting the values, we get $n = \frac{\sin((60^{\circ} + 60^{\circ}) / 2)}{\sin(60^{\circ} / 2)}$.$n = \frac{\sin(120^{\circ} / 2)}{\sin(30^{\circ})} = \frac{\sin(60^{\circ})}{\sin(30^{\circ})}$.Since $\sin(60^{\circ}) = \frac{\sqrt{3}}{2}$ and $\sin(30^{\circ}) = \frac{1}{2}$, we have $n = \frac{\sqrt{3} / 2}{1 / 2} = \sqrt{3}$.The value of $\sqrt{3}$ is approximately $1.732$.

If the angle of minimum deviation produced by an equilateral prism is equal to the angle of the prism, then the refractive index of the material of the prism is nearly

Similar Questions

The angle of deviation $(\delta)$ vs angle of incidence $(i)$ is plotted for a prism. Pick the correct statement:-

$A$ triangular prism of glass is shown in the figure. $A$ ray incident normally to one face is totally reflected,if $\theta = 45^o$. The index of refraction of glass is

In the visible region, the dispersive powers and the mean angular deviations for crown and flint glass prisms are $\omega, \omega^{\prime}$ and $d, d^{\prime}$ respectively. The condition for obtaining dispersion without deviation, when the two prisms are combined, is:

Minimum deviation is observed with a prism having angle of prism $A$,angle of deviation $\delta$,angle of incidence $i$,and angle of emergence $e$. We then have generally

When white light passes through an achromatic combination of prisms,what is observed?

Vedclass Test Series

Exam Paper Generator

Online Exam Module