If the bond formation energy of the H-H bond | vedclass

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(B) The bond dissociation energy is the energy required to break one mole of bonds in a gaseous substance.For the reaction $H_{2(g)} \longrightarrow 2

Vedclass · Accepted Answer

$216.5$

Vedclass · Answer

(B) The bond dissociation energy is the energy required to break one mole of bonds in a gaseous substance.For the reaction $H_{2(g)} \longrightarrow 2H_{(g)}$,the enthalpy change $\Delta_{r} H^{\circ}$ is equal to the bond dissociation energy.Since the bond formation energy of $H-H$ is $-433 \ kJ \ mol^{-1}$,the bond dissociation energy for $1 \ mol$ of $H_{2(g)}$ is $+433 \ kJ \ mol^{-1}$.Therefore,the bond dissociation energy for $0.5 \ mol$ of $H_{2(g)}$ is $0.5 \ mol 	imes 433 \ kJ \ mol^{-1} = 216.5 \ kJ$.

If the bond formation energy of the $H-H$ bond is $-433 \ kJ \ mol^{-1}$,find the bond dissociation energy for $0.5 \ mol$ of $H_{2(g)}$. (in $kJ$)

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